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  • question_answer
     The dimensions of \[{{({{\mu }_{0}}{{\varepsilon }_{0}})}^{-1/2}}\] are                        [AIPMT (M) 2012]

    A)  \[[{{L}^{1/2}}T{{-}^{1/2}}]\]           

    B)       \[[{{L}^{-1}}T]\]        

    C)  \[[L{{T}^{-1}}]\]        

    D)       \[[{{L}^{1/2}}{{T}^{1/2}}]\]

    Correct Answer: C

    Solution :

    \[{{({{\mu }_{0}}{{\varepsilon }_{0}})}^{-1/2}}\] is velocity of light
    Hence  \[c=\frac{1}{\sqrt{({{\mu }_{0}}{{\varepsilon }_{0}})}}=[L{{T}^{-1}}]\]


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