NEET Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन NEET PYQ-Fluid Mechanics, Surface Tension and Viscosity

  • question_answer
    The dimensions of universal gravitational constant are:                                [AIPMT (S) 2004]

    A)  \[[{{M}^{-1}}\,{{L}^{3}}\,{{T}^{-2}}]\]

    B)  \[[M{{L}^{2}}\,{{T}^{-1}}]\]

    C)  \[[{{M}^{-2}}\,{{L}^{3}}\,{{T}^{-2}}]\]     

    D)       \[[{{M}^{-2}}\,{{L}^{2}}\,{{T}^{-1}}]\]

    Correct Answer: A

    Solution :

    Key Idea: Substitute the dimensions for the quantities involved in an expression written for gravitational constant. According to Newton's law of gravitation, the force of attraction between two masses \[{{m}_{1}}\] and \[{{m}_{2}}\] separated by a distance r is,
    \[F=\frac{G\,\,\,{{m}_{1}}\,{{m}_{2}}}{{{r}^{2}}}\Rightarrow G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\]
    Substituting the dimensions for the quantities on the right hand side, we obtain dimensions of
                \[G=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}\]
    \[=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]       


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