A) 5.0 g
B) 10.0 g
C) 20.0 g
D) 2.5 g
Correct Answer: B
Solution :
[b] Force of surface tension balances the weight of water in capillary tube. |
\[{{F}_{S}}=2\pi rTcos\,\theta =mg\] |
Here, T and \[\theta \] are constant |
So, \[m\propto ~r\] |
Hence, \[\frac{{{m}_{2}}}{5.0}=\frac{2r}{r}\] |
\[\Rightarrow {{m}_{2}}=10.0\,g\] |
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