A) \[R-F>R-Cl>R-Br>R-I\]
B) \[R-I>R-Br>R-Cl>R-F\]
C) \[R-I>R-Cl>R-Br>R-F\]
D) \[R-F>R-I>R-Br>R-Cl\]
Correct Answer: B
Solution :
[b] F, Cl, Br and I are the elements of VIIA group. In a group atomic, radii increases from top to bottom and the bond dissociation energy decreases as \[RF>RCl>RBr>RI\] |
So, during dehydrohalogenation \[R-I\] bond breaks more easily than \[R-F\] bond. Hence, order of reactivity will be- |
\[RI>RBr>RCl>R~-\text{ }F\] |
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