question_answer

The solubility product of \[Agl\] at \[25{}^\circ C\] is\[1.0\times {{10}^{-16}}mo{{l}^{2}}{{L}^{-2}}\]. The solubility of \[Agl\] in \[{{10}^{-4}}N\] solution of \[KI\] at \[25{}^\circ C\] is approximately (in \[mol\text{ }{{L}^{-1}}\]):                                                                                                                                                [AIPMT 2003]

A)  \[1.0\times {{10}^{-10}}\]

B)                   \[1.0\times {{10}^{-8}}\]        

C)  \[1.0\times {{10}^{-16}}\]

D)                   \[1.0\times {{10}^{-12}}\]

Correct Answer: D

Solution :

           

For binary electrolyte

where s = solubility in mol/L

or

solubility of  in  solution