A) \[p{{H}_{1}}>p{{H}_{2}}>~p{{H}_{3}}>p{{H}_{4}}\]
B) \[p{{H}_{1}}<p{{H}_{2}}<p{{H}_{3}}<p{{H}_{4}}\]
C) \[p{{H}_{1}}<p{{H}_{2}}<p{{H}_{3}}<~p{{H}_{4}}\]
D) \[p{{H}_{1}}>p{{H}_{2}}>p{{H}_{3}}>p{{H}_{4}}\]
Correct Answer: A
Solution :
The correct order of pH of isomolar solution in sodium oxide (pH1) sodium sulphide (pH2), sodium selenide (pH3) and sodium telluride (pH4) is pH1 > pH2 > pH3 > pH4 because in aqueous solution, they are hydrolysed as follows. |
Order of acidic strength |
Order of neutralisation of NaOH |
Hence, their aqueous solutions have the following order of basic character due to neutralisation of NaOH with |
H2O, H2S, H2Se and H2Te. |
Na2O > Na2S > Na2Se > Na2Te |
( pH of basic solution is higher than acidic or least basic solution) |
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