A) \[0.2\text{ }kg/{{m}^{3}}\]
B) \[0.1\text{ }kg/{{m}^{3}}\]
C) \[0.02\text{ }kg/{{m}^{3}}\]
D) \[0.5\text{ }kg/{{m}^{3}}\]
Correct Answer: A
Solution :
| [a] |
| \[PM=\rho RT\Rightarrow \rho =\frac{PM}{RT}\] |
| \[P=249\times {{10}^{3}}\,N/{{m}^{2}}\] |
| \[M=2\times {{10}^{-3}}kg\] |
| \[T=300\,K\]\[\therefore \rho =\frac{(249\times {{10}^{3}})(2\times {{10}^{-3}})}{8.3\times 300}=\frac{0.2\,kg}{{{m}^{3}}}\] |
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