NEET Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव NEET PYQ-Magnetic Effects Of Current

  • question_answer
    A current loop consists of two identical semicircular parts each of radius R, one lying in the \[x-y\] plane and the other in \[x-z\] plane. If the current in the loop is i. The resultant magnetic field due to the two semicircular parts at their common centre is                [AIPMT (M) 2010]

    A)  \[\frac{{{\mu }_{0}}i}{2\sqrt{2}R}\]     

    B)       \[\frac{{{\mu }_{0}}i}{2R}\]

    C)  \[\frac{{{\mu }_{0}}i}{4R}\]                

    D)       \[\frac{{{\mu }_{0}}i}{\sqrt{2}R}\]

    Correct Answer: A

    Solution :

    [a] The magnetic field at centre O for each semicircular parts each of radius R,
    \[{{B}_{1}}={{B}_{2}}=\frac{{{\mu }_{0}}i}{4R}\]
    The magnetic field at their common centre
    \[\overset{\to }{\mathop{\mathbf{B}}}\,=\overset{\to }{\mathop{{{\mathbf{B}}_{1}}}}\,+\overset{\to }{\mathop{{{\mathbf{B}}_{2}}}}\,\]
    \[B=\sqrt{B_{1}^{2}+B_{2}^{2}}\]
    \[=\sqrt{{{\left( \frac{{{\mu }_{0}}i}{4R} \right)}^{2}}+{{\left( \frac{{{\mu }_{0}}i}{4R} \right)}^{2}}}\]
    \[B=\frac{{{\mu }_{0}}i}{2\sqrt{2}R}\]


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