NEET Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव NEET PYQ-Magnetic Effects Of Current

  • question_answer
    Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is                                                  [AIPMT (M) 2011]

    A)  \[\frac{{{\mu }_{0}}qf}{2R}\]

    B)                   \[\frac{{{\mu }_{0}}q}{2f\,R}\]

    C)  \[\frac{{{\mu }_{0}}q}{2\pi f\,R}\]       

    D)        \[\frac{{{\mu }_{0}}qf}{2\pi R}\]

    Correct Answer: A

    Solution :

    [a] We know
    \[B=\frac{{{\mu }_{0}}i}{2R}\]
    \[q=it\Rightarrow i=\frac{q}{t}=qf\]        \[\left[ \because \,\,f=\frac{1}{t} \right]\]
    \[B=\frac{{{\mu }_{0}}qf}{2R}\]


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