A) \[\frac{m{{a}_{0}}}{e}\text{west},\frac{2m{{a}_{0}}}{e{{v}_{0}}}\text{up}\]
B) \[\frac{m{{a}_{0}}}{e}\text{west},\frac{2m{{a}_{0}}}{e{{v}_{0}}}\text{dwon}\]
C) \[\frac{m{{a}_{0}}}{e}\text{east},\frac{3m{{a}_{0}}}{e{{v}_{0}}}\text{up}\]
D) \[\frac{m{{a}_{0}}}{e}\text{west},\frac{3m{{a}_{0}}}{e{{v}_{0}}}\text{down}\]
Correct Answer: B
Solution :
| [b] Initial acceleration, \[{{a}_{0}}=\frac{eE}{m}\] (i) |
| \[\Rightarrow \]\[E=\frac{{{a}_{0}}m}{e}\therefore \frac{e{{v}_{0}}B+eE}{m}=3{{a}_{0}}\] |
| or \[e{{v}_{0}}B+eE=3{{a}_{0}}m\] |
| \[\therefore \] \[e{{v}_{0}}B=3m{{a}_{0}}-eE\] |
| \[\Rightarrow \] \[=3m{{a}_{0}}-m{{a}_{0}}\] [from eq. (1)] |
| \[\Rightarrow \] \[e{{v}_{0}}B=2m{{a}_{0}}\] |
| \[\therefore \] \[B=\frac{2m{{a}_{0}}}{e{{v}_{0}}}\] |
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