A) \[\frac{{{\mu }_{0}}ne}{2\pi r}\]
B) zero
C) \[\frac{{{\mu }_{0}}{{n}^{2}}e}{r}\]
D) \[\frac{{{\mu }_{0}}ne}{2r}\]
Correct Answer: D
Solution :
[d] As \[I=\frac{q}{t}\] |
So, for an electron revolving in a circular orbit of radius r |
\[q=e\] and \[t=T\] |
\[\Rightarrow \] \[I=\frac{e}{T}=\frac{e}{2\pi /\omega }=\frac{\omega e}{2\pi }=\frac{2\pi ne}{2\pi }=ne\] |
The magnetic field produced at the centre is |
\[B=\frac{{{\mu }_{0}}I}{2R}=\frac{{{\mu }_{0}}ne}{2r}\] |
You need to login to perform this action.
You will be redirected in
3 sec