• # question_answer In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows $p=\frac{{{a}^{3}}{{b}^{2}}}{cd}%,$ Error in P is   [NEET 2013] A) 14% B) 10%                  C) 7% D) 4%

 Here, $P=\frac{{{a}^{3}}{{d}^{2}}}{cd}$ $\therefore$      $\frac{\Delta P}{P}\times 100$ $=\left( \frac{3\Delta P}{a}+\frac{2\Delta b}{b}+\frac{\Delta c}{c}+\frac{\Delta d}{d} \right)\times 100$ $=3\frac{\Delta a}{a}\times 100+2\frac{\Delta b}{b}\times 100+\frac{\Delta c}{c}$ $\times 100+\frac{\Delta d}{d}\times 100$ $=3\times 1+2\times 2+3+4$ $=3+4+3+4=14%$