NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    A particle of mass M is revolving along a circle of radius R and another particle of mass m is revolving in a circle of radius r. If time periods of both particles are same, then the ratio of their angular velocities is:              [AIPMT 2001]

    A) 1

    B) \[\frac{R}{r}\]

    C) \[\frac{r}{R}\]

    D) \[\sqrt{\frac{R}{r}}\]

    Correct Answer: A

    Solution :

    Angular velocity of particle is
                            \[\omega =\frac{2\pi }{T}\] or \[\omega \propto \,\frac{1}{T}\]
                It simply implies that  does not depend on mass of the body and radius of the circle.
                \[\therefore \]      \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\]
                but time period is given same, i.e., \[{{T}_{1}}={{T}_{2}}\]
                Hence,  \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=\frac{1}{1}\]


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