A) \[\overrightarrow{E}=\hat{i}(2xy-{{z}^{3}})+\hat{j}x{{y}^{2}}+\hat{k}3{{z}^{2}}x\]
B) 10kg
C) 20kg
D) \[2\times {{10}^{4}}J{{T}^{-1}}\]
Correct Answer: D
Solution :
Key Idea: According to Newtons second law of motion, force = mass \[\times \] acceleration. |
Here, \[=k(x+a)\] |
\[k,{{k}_{0}},{{k}_{1}}\] |
\[9\times {{10}^{17}}\] |
\[3\times {{10}^{16}}\] |
\[9\times {{10}^{15}}\] \[3\times {{10}^{19}}\] |
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