A) 1.2 m
B) 0.6 m
C) zero
D) 0.4 m
Correct Answer: D
Solution :
Force, \[F=\mu \,mg\] Retardation of the block on the belt |
\[a=\frac{F}{m}=\frac{\mu \,mg}{m}=\mu g\] |
Form, \[{{v}^{2}}={{u}^{2}}+2as\] |
\[0={{(2)}^{2}}-2(\mu g)s\] |
\[s=\frac{4}{2\times 0.5\times 10}=0.4\,m\] |
You need to login to perform this action.
You will be redirected in
3 sec