NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is \[{{45}^{o}},\] the speed of the car is [AIPMT (S) 2012]

    A) \[20\,m{{s}^{-1}}\]

    B) \[30\,m{{s}^{-1}}\]

    C) \[5\,m{{s}^{-1}}\]

    D) \[10\,m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    The angle of banking \[\tan \theta =\frac{{{v}^{2}}}{rg}\]
                Given, \[\theta ={{45}^{o}},r=90\,m\] and \[g=10\,m/{{s}^{2}}\]
                            \[\tan {{45}^{o}}=\frac{{{v}^{2}}}{90\times 10}\]
                            \[v=\sqrt{90\times 10\times \tan {{45}^{o}}}\]
                Speed of car \[v=30\text{ }m/s\]


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