A) k, A and M
B) k, x, M
C) k, A
D) k, x
Correct Answer: C
Solution :
| In SHM, the total energy = potential energy + kinetic energy |
| or \[E=U+K\] |
| \[=\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}+\frac{1}{2}m{{\omega }^{2}}({{A}^{2}}-{{x}^{2}})\] |
| \[=\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}\] |
| \[=\frac{1}{2}k{{A}^{2}}\] |
| where \[k=\] force constant \[=m{{\omega }^{2}}\] |
| Thus, total energy depends on k and A. |
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