A) 2
B) 3
C) 4
D) 1
Correct Answer: A
Solution :
Given, that two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius \[\frac{r}{2}\] and lighter one in radius r as shown in figure. |
As, lighter stone is n times that of the value of heavier stone when they experience same centripetal forces, we get |
\[{{({{F}_{c}})}_{heavier}}={{({{F}_{c}})}_{lighter}}\] |
\[\Rightarrow \] \[\frac{2m{{(v)}^{2}}}{(r/2)}=\frac{m{{(nv)}^{2}}}{r}\] |
\[\Rightarrow \] \[{{n}^{2}}=4\] |
\[\Rightarrow \] \[n=2\] |
You need to login to perform this action.
You will be redirected in
3 sec