Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a 1 frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is [NEET 2015 ] |
A) 2 N
B) 6 N
C) 8 N
D) 18 N
Correct Answer: B
Solution :
Given, \[{{m}_{A}}=4\,kg\] |
So total mass \[(M)=4+2+1=7kg\] |
Now, \[F=Ma\Rightarrow 14=7a\Rightarrow a=2m/{{s}^{2}}\] |
FED of block A, |
\[F=F'=4a\Rightarrow F'=14-4\times 2\Rightarrow F'=6N\] |
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