A) 3 kg
B) 5 kg
C) 7 kg
D) 17 kg
Correct Answer: B
Solution :
We have \[{{p}_{1}}+{{p}_{2}}+{{p}_{3}}=0\] \[[\because P=mv]\] |
\[\therefore \] \[1\times 12i+2\times 8j+{{p}_{3}}=0\] |
\[\Rightarrow \] \[12i+16j+{{p}_{3}}=0\] |
\[\Rightarrow \] \[{{p}_{3}}=-(12i+16j)\] |
\[\therefore \] \[{{p}_{3}}=\sqrt{{{(12)}^{2}}+{{(16)}^{2}}}\] |
\[\sqrt{144+256}\] |
\[=20kg-m/s\] |
Now, \[{{p}_{3}}={{m}_{3}}{{v}_{3}}\] |
\[\Rightarrow \] \[{{m}_{3}}=\frac{{{p}_{3}}}{{{v}_{3}}}=\frac{20}{4}=5kg\] |
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