A) 14 m/s
B) 3 m/s
C) 3.92 m/s
D) 5 m/s
Correct Answer: A
Solution :
| Key Idea: In a horizontal circle, tension in the string provides the necessary centripetal force. For a ball to move in horizontal circle, the ball should satisfied the condition: |
| Tension in the string = Centripetal force |
| \[\Rightarrow \] \[{{T}_{\max }}=\frac{M{{v}^{2}}_{\max }}{R}\] |
| \[\Rightarrow \] \[{{v}_{\max }}=\sqrt{\frac{{{T}_{\max }}.R}{M}}\] (i) |
| Making substitution, we obtain |
| \[{{v}_{\max }}=\sqrt{\frac{25\times 1.96}{0.25}}\] |
| \[=\sqrt{196}\] |
| \[=14\,m/s\] |
| Note: In a vertical circle, the tension at the highest point in zero and at lowest pint is maximum. |
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