A) \[0.1\text{ }m/{{s}^{2}}\]
B) \[0.15\text{ }m/{{s}^{2}}\]
C) \[0.18\text{ }m/{{s}^{2}}\]
D) \[0.2\text{ }m/{{s}^{2}}\]
Correct Answer: A
Solution :
| \[\frac{1}{2}m{{v}^{2}}=E\Rightarrow \frac{1}{2}\left( \frac{10}{1000} \right){{v}^{2}}=8\times {{10}^{-4}}\] |
| \[\Rightarrow \]\[{{v}^{2}}=16\times {{10}^{-2}}\Rightarrow v=4\times {{10}^{-1}}=0.4\,\,m/s\] |
| Now, \[{{v}^{2}}={{u}^{2}}+2{{a}_{t}}s\] |
| \[(s=4\pi R)\] |
| \[\Rightarrow \] \[\frac{16}{100}={{0}^{2}}+2{{a}_{t}}\left( 4\times \frac{22}{7}\times \frac{6.4}{100} \right)\] |
| \[\Rightarrow \] \[{{a}_{t}}=\frac{16}{100}\times \frac{7\times 100}{8\times 22\times 6.4}=0.1\,\,m/{{s}^{2}}\] |
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