A) \[1:\sqrt{3}\]
B) \[1:2\sqrt{3}\]
C) \[1:\sqrt{2}\]
D) \[\sqrt{2}:1\]
Correct Answer: A
Solution :
[a] |
\[{{v}^{2}}={{u}^{2}}+2as\] |
\[0={{u}^{2}}2g\text{ }sin\theta S\] |
\[S=\frac{{{u}^{2}}}{2g\sin \theta }\] |
\[S\propto \frac{1}{\sin \theta }\] |
\[\frac{{{x}_{1}}}{{{x}_{2}}}=\frac{{{\sin }_{2}}\theta }{{{\sin }_{1}}\theta }=\frac{\sin 30{}^\circ }{\sin 60{}^\circ }=\frac{1}{\sqrt{3}}\] |
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