A) 16.758 MeV
B) 1.6758 MeV
C) 0.16758 MeV
D) 0.016758 MeV
Correct Answer: C
Solution :
[c] \[\underset{(Mass=34.96903\,amu)}{\mathop{_{16}{{S}^{35}}}}\,\xrightarrow[{}]{-\beta }\,\,\underset{(Mass=34.96885)}{\mathop{_{17}{{C}^{35}}}}\,\] |
Mass defect = (34.96903 34.96885) amu |
= 0.00018 amu |
Energy \[=0.00018\times 931\text{ }MeV=0.16758\text{ }MeV\] |
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