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NEET Physics Nuclear Physics And Radioactivity NEET PYQ-Nuclear Physics

  • question_answer
    A nuclear decay is expressed as                                                    [AIPMT 2000]
    \[_{6}{{C}^{11}}\to {{\,}_{5}}{{B}^{11}}+\,{{\beta }^{+}}+X\]  
    Then the unknown particle X is:

    A)  neutron

    B)   antineutrino

    C)  proton         

    D) neutrino

    Correct Answer: B

    Solution :

    Key Idea: In a nuclear reaction conservation of charge number and mass number must hold good.
       Let Z be the charge number and A the mass number of particle X, then conservation of charge number gives.
                \[6=5+1+Z\]
       \[\Rightarrow \] \[Z=0\]
       Conservation of mass number gives,
                \[11=11+0+A\]
       \[\Rightarrow \] \[A=0\]
       X is a particle of zero charge and zero mass. This particle may be neutrino or antineutrino. With positive \[\beta -\]particle, neutrino is emitted and with negative \[\beta -\]particle, antineutrino is emitted.
       Thus, in our case neutrino will be emitted.


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