A) \[M\left( N,\text{ }Z \right)=N{{M}_{n}}+Z{{M}_{p}}-B{{e}^{2}}\]
B) \[M\left( N,Z \right)=N{{M}_{n}}+Z{{M}_{p}}+B/{{c}^{2}}\]
C) \[M\left( N,\text{ }Z \right)=N{{M}_{n}}+Z{{M}_{p}}-B/{{c}^{2}}\]
D) \[M\left( N,\text{ }Z \right)=N{{M}_{n}}+Z{{M}_{p}}+B/{{c}^{2}}\]
Correct Answer: C
Solution :
Binding energy of a nucleus containing N neutrons and Z protons is |
\[B=[N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)]{{c}^{2}}\] |
\[\Rightarrow \] \[\frac{B}{{{c}^{2}}}=N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)\] |
\[\Rightarrow \] \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}-B/{{c}^{2}}\] |
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