A) 73
B) 74
C) 75
D) 72
Correct Answer: D
Solution :
| Let radius of \[_{4}^{9}Be\] nucleus be r. Then radius of germanium (Ge) nucleus will be \[2\,r\]. |
| Radius of a nucleus is given by |
| \[R={{R}_{0}}\,\,{{A}^{1/3}}\] |
| \[\therefore \] \[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{A}_{1}}}{{{A}_{2}}} \right)}^{1/3}}\] |
| \[\Rightarrow \] \[\frac{r}{2r}={{\left( \frac{9}{{{A}_{2}}} \right)}^{13}}\] \[(\because \,{{A}_{1}}=9)\] |
| \[\Rightarrow \] \[{{\left( \frac{1}{2} \right)}^{3}}=\frac{9}{{{A}_{2}}}\] |
| Hence, \[{{A}_{2}}=9\times {{(2)}^{3}}\] |
| \[=9\times 8\] |
| = 72 |
| Thus, in germanium (Ge) nucleus number of nucleus is 72. |
You need to login to perform this action.
You will be redirected in
3 sec
