A) isobar of parent
B) isomer of parent
C) isotone of parent
D) isotope of parent
Correct Answer: D
Solution :
Let, the radioactive substance be \[_{Z}^{A}X\] |
Radioactive transition is given by |
\[_{Z}^{A}X\xrightarrow{-\alpha }_{Z-2}^{A-4}X\xrightarrow{-2\beta }\,_{Z}^{A-4}X\] |
The atoms of element having same atomic number but different mass numbers are called isotopes. |
So, \[_{Z}^{A}X\] and \[_{Z}^{A-4}X\] are isotopes. |
You need to login to perform this action.
You will be redirected in
3 sec