A) 23.6 MeV
B) 2.2 MeV
C) 28.0 MeV
D) 30.2 MeV
Correct Answer: A
Solution :
Mass of \[_{1}{{H}^{2}}=2.01478\,amu\] |
Mass of \[_{2}H{{e}^{4}}=4.00388\,amu\] |
Mass of two deuterium \[=2\times 2.01478\] |
= 4.02956 amu |
Energy equivalent to \[_{2}{{H}^{2}}\] |
\[=4.02956\times 1.2\] |
\[=4.4\text{ }MeV\] |
Energy equivalent to \[_{2}{{H}^{4}}\] |
\[=4.00388\times 7=28\text{ }MeV\] |
Energy released \[=(28-4.4)\] |
\[=23.6\text{ }MeV\] |
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