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NEET Physics Nuclear Physics And Radioactivity NEET PYQ-Nuclear Physics

  • question_answer
    The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is              [AIPMT (M) 2010]

    A)  23.6 MeV     

    B)  2.2 MeV

    C)  28.0 MeV   

    D)  30.2 MeV

    Correct Answer: A

    Solution :

    Mass of \[_{1}{{H}^{2}}=2.01478\,amu\]
    Mass of \[_{2}H{{e}^{4}}=4.00388\,amu\]
    Mass of two deuterium \[=2\times 2.01478\]
    = 4.02956 amu
    Energy equivalent to \[_{2}{{H}^{2}}\]
    \[=4.02956\times 1.2\]
    \[=4.4\text{ }MeV\]
    Energy equivalent to \[_{2}{{H}^{4}}\]
    \[=4.00388\times 7=28\text{ }MeV\]
    Energy released \[=(28-4.4)\]
    \[=23.6\text{ }MeV\]


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