A) x\[{{h}^{2}}{{v}^{2}}/2M{{c}^{2}}\]
B) zero
C) \[hv\]
D) \[M{{c}^{2}}-hv\]
Correct Answer: A
Solution :
| Momentum of a photon |
| \[p=\frac{hv}{c}\] |
| Hence, Recoil energy |
| \[E=\frac{{{p}^{2}}}{2M}\] |
| \[\therefore \] \[E=\frac{{{\left( \frac{hv}{c} \right)}^{2}}}{2M}\] |
| or \[E=\frac{{{h}^{2}}{{v}^{2}}}{2M{{c}^{2}}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
