2. Solved Papers
  3. NEET
  4. Physics
  5. Nuclear Physics And Radioactivity

NEET Physics Nuclear Physics And Radioactivity NEET PYQ-Nuclear Physics

  • question_answer
    The binding energy per nucleon of \[_{3}^{7}Li\] and \[_{2}^{4}He\] nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction\[_{3}^{7}Li+_{1}^{1}H\to _{2}^{4}He\]\[+_{2}^{4}He+Q,\] the value of energy Q released is                                                                                     [NEET 2014]

    A)  19.6 MeV        

    B)       - 2.4 MeV

    C)  8.4 MeV           

    D)  17.3 MeV

    Correct Answer: D

    Solution :

    The binding energy for \[{{\,}_{1}}{{H}^{1}}\] is around zero and also not given in the question so we can ignore it
    \[Q=24(4\times 7.06)-7\times (5.60)\]
         \[=(8\times 7.06)-(7\times 5.60)\]
         \[=(56.48-39.2)MeV\]
       \[=17.28MeV\simeq 17.3MeV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner