A) \[{{\left( \frac{53}{13} \right)}^{\frac{1}{3}}}{{R}_{Al}}\]
B) \[\frac{5}{3}{{R}_{Al}}\]
C) \[\frac{3}{5}{{R}_{Al}}\]
D) \[{{\left( \frac{13}{53} \right)}^{\frac{1}{3}}}{{R}_{Al}}\]
Correct Answer: B
Solution :
| Radius of the nucleus is given by |
| \[R={{R}_{0}}{{A}^{1/3}}\Rightarrow R\propto {{A}^{1/3}}\] |
| \[\frac{{{R}_{Al}}}{{{R}_{Te}}}={{\left( \frac{{{A}_{Al}}}{{{A}_{Te}}} \right)}^{1/3}}={{\left( \frac{27}{125} \right)}^{1/3}}=\frac{3}{5}\] |
| \[{{R}_{Te}}=\frac{5}{3}{{R}_{Al}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
