A) 4
B) 6
C) 8
D) 2
Correct Answer: A
Solution :
| [a] Key Idea: |
| (i) Number of optical isomers \[={{2}^{n}}\]where, n = number of dissimilar asymmetric carbon atoms. |
| (ii) Number of geometrical isomers \[={{2}^{n}}\] where, n = number of double bond only when the two ends of the chain are different |
| \[C{{H}_{3}}CH=CH-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\overset{*}{\mathop{C}}}\,H-C{{H}_{3}}\] |
| Here, number of optical isomers = 21 = 2 |
| Number of geometrical isomers = 21 = 2 |
| Hence, number of stereoisomers = 2 + 2=4 |
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