A) decrease by 2 times
B) decrease by 4 times
C) increase by 4 times
D) increase by 2 times
Correct Answer: A
Solution :
| We have |
| \[\lambda =\frac{12.27}{\sqrt{V}}\] |
| So, \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\sqrt{\frac{{{V}_{2}}}{{{V}_{1}}}}\] |
| \[{{\lambda }_{2}}={{\lambda }_{1}}\sqrt{\frac{{{V}_{1}}}{{{V}_{2}}}}\] |
| \[{{\lambda }_{2}}={{\lambda }_{1}}\sqrt{\frac{25}{100}}\] |
| \[{{\lambda }_{2}}={{\lambda }_{1}}\sqrt{\frac{1}{4}}=\frac{{{\lambda }_{1}}}{2}\] |
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