A) 0.65 eV
B) 1.0 eV
C) 1.3 eV
D) 1.5 eV
Correct Answer: B
Solution :
| For photo electric equation |
| \[{{(KE)}_{\max }}=hv-{{\phi }_{0}}\] |
| For the first condition |
| \[0.5=E-{{\phi }_{0}}\] (i) |
| For the second condition |
| \[0.8-1.2E-{{\phi }_{0}}\] (ii) |
| From Eqs. (i) and (ii) |
| \[0.5=E-{{\phi }_{0}}\] |
| and \[0.8=1.2E-{{\phi }_{0}}\] |
| \[-0.3=-0.2E\] |
| \[E=\frac{0.3}{0.2}1.5eV\] |
| From expression (i) |
| \[0.5=1.5-{{\phi }_{0}}\Rightarrow {{\phi }_{0}}=0.5-0.5=1eV\] |
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