A) \[\text{4 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{15}}}\,{{\text{H}}_{\text{Z}}}\]
B) \[5\times {{10}^{15}}\,{{H}_{Z}}\]
C) \[1.6\times {{10}^{15}}\,{{H}_{Z}}\]
D) \[2.5\times {{10}^{15}}\,{{H}_{Z}}\]
Correct Answer: C
Solution :
Energy released from emission of electron |
\[E=(-3.4)-(-13.6)\] |
\[=10.2\,eV\] |
From photo electric equation. Work function |
\[\phi =E-eV=hv\] |
\[v=\frac{E-eV}{h}\] |
\[=\frac{(10.2-3.57)e}{6.67\times {{10}^{-34}}}\] |
\[v=\frac{6.63\times 1.6\times {{10}^{-19}}}{6.67\times {{10}^{-34}}}\] |
\[=1.6\times {{10}^{15}}Hz\] |
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