A) \[4\lambda \]
B) \[5\lambda \]
C) \[\frac{5}{2}\lambda \]
D) \[3\lambda \]
Correct Answer: D
Solution :
| [d] \[eV=\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{0}}}\] (i) |
| \[eV/4=\frac{hc}{2\lambda }-\frac{hc}{{{\lambda }_{0}}}\] (ii) |
| From equation (i) and (ii) |
| \[\Rightarrow \] \[4=\frac{\frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}}}{\frac{1}{2\lambda }-\frac{1}{{{\lambda }_{0}}}}\] |
| On solving \[{{\lambda }_{0}}=3\lambda \] |
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