A) \[{{10}^{2}}V\]
B) \[{{10}^{3}}V\]
C) \[{{10}^{4}}V\]
D) \[10\,V\]
Correct Answer: C
Solution :
[c] \[\lambda =\frac{12.27}{\sqrt{V}}\overset{o}{\mathop{A}}\,\] |
\[\sqrt{V}=\frac{12.27\times {{10}^{-10}}}{1.227\times {{10}^{-11}}}={{10}^{2}}\] |
\[\therefore V={{10}^{4}}\,\text{volts}\] |
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