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NEET Physics Photo Electric Effect, X- Rays & Matter Waves NEET PYQ-Photo Electric Effect,X-Rays

  • question_answer
    The following particles are moving with the same velocity, then maximum de-Broglie wavelength will be for:                                                                                                                                                                              [AIPMT 2002]

    A)  proton 

    B)       \[\alpha \]-particle

    C)       neutron 

    D)           \[\beta \]-particle

    Correct Answer: D

    Solution :

    de-Broglie wavelength is given by
    \[\lambda =\frac{h}{mv}\]
    For same velocity,
    \[\lambda \,\propto \frac{1}{m}\]
    Out of the given particles, the mass of \[\beta \]-particle which is a fast moving electron, is minimum. Thus, de-Broglie wavelength is maximum for     \[\beta \]-particle.


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