A) 0.5 m
B) 0.6 m
C) 0.7 m
D) 0.2 m
Correct Answer: B
Solution :
| Loss in \[KE=\] Gain in spring energy |
| \[\frac{1}{2}m{{v}^{2}}\left[ 1+\frac{{{K}^{2}}}{{{R}^{2}}} \right]=\frac{1}{2}k\,x_{\max }^{2}\] |
| where k is the force constant. |
| Given, \[v=4\text{ }m/s,\text{ }m=3\text{ }kg,\,\,k=200\,N/m\] |
| For solid cylinder, \[\frac{{{K}^{2}}}{{{R}^{2}}}=\frac{1}{2}\] |
| \[\therefore \] \[\frac{1}{2}\times 3\times {{(4)}^{2}}\left[ 1+\frac{1}{2} \right]=\frac{1}{2}\times 200\times x_{\max }^{2}\] |
| The maximum compression in the spring |
| \[x_{\max }^{{}}=0.\,6\text{m}\] |
You need to login to perform this action.
You will be redirected in
3 sec
