A) 10 : 7
B) 5 : 7
C) 7 : 10
D) (4) 2 : 5
Correct Answer: B
Solution :
[b] \[{{\text{K}}_{\text{t}}}\text{=}\frac{\text{1}}{\text{2}}\text{m}{{\text{v}}^{\text{2}}}\] |
\[{{\text{K}}_{\text{t}}}\text{+}{{\text{K}}_{\text{r}}}\text{=}\frac{1}{2}m{{v}^{2}}+\frac{1}{2}|{{\omega }^{2}}=\frac{1}{2}m{{v}^{2}}+\frac{1}{2}\left( \frac{2}{5}m{{r}^{2}} \right){{\left( \frac{v}{r} \right)}^{2}}\] |
\[=\frac{7}{10}m{{v}^{2}}\] |
So, \[\] |
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