question_answer

The intensity at the maximum in a Young's double slit experiment is \[{{I}_{0}}\]. Distance between two slits is \[d=5\lambda ,\] where \[\lambda \] the wavelength of light is used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance \[D=10\,d\]?   [NEET - 2016]

A) \[{{I}_{0}}\]

B) \[\frac{{{I}_{0}}}{4}\]

C) \[\frac{3}{4}{{I}_{0}}\]

D) v

Correct Answer: D

Solution :

[d] Path difference

So, intensity at the desired point is