A) \[3.3\,\overset{o}{\mathop{A}}\,\]
B) \[3.9\,\overset{o}{\mathop{A}}\,\]
C) \[4.3\,\overset{o}{\mathop{A}}\,\]
D) \[4.8\,\overset{o}{\mathop{A}}\,\]
Correct Answer: C
Solution :
| The distance between any two nearest neighbours (atoms) in body centered lattice is \[\frac{\sqrt{3}}{2}a,\] where a is lattice parameter. |
| We have given |
| \[\frac{\sqrt{3}}{2}a=3.7\] |
| \[\therefore \] \[a=\frac{3.7\times 2}{\sqrt{3}}=\frac{3.7\times 2}{1.773}=4.3\,\overset{o}{\mathop{A}}\,\] |
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