A) 1
B) 2
C) 4
D) 9
Correct Answer: B
Solution :
| Key Idea: In case of bcc lattice, there are eight atoms at the eight corners of the unit cell and one atom at the body centre. |
| Number of atoms per unit cell is given by |
| \[N={{N}_{b}}+\frac{{{N}_{f}}}{2}\times \frac{{{N}_{c}}}{8}\] |
| where \[{{N}_{b}}=\] number of atoms centred in this body |
| \[{{N}_{f}}=\] number of atoms centred in the face |
| \[{{N}_{c}}=\] number of atoms centred at the corner |
| For bcc structure, \[{{N}_{b}}=1,\text{ }{{N}_{f}}=0\] and \[{{N}_{c}}=8\] |
| \[\therefore \] \[N=1+\frac{0}{2}+\frac{8}{8}=2\] |
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