A) \[1.27\,\overset{o}{\mathop{A}}\,\]
B) \[5.08\,\overset{o}{\mathop{A}}\,\]
C) \[2.54\,\overset{o}{\mathop{A}}\,\]
D) \[3.59\,\overset{o}{\mathop{A}}\,\]
Correct Answer: D
Solution :
| Interatomic spacing for a fcc lattice |
| \[r={{\left[ {{\left( \frac{a}{2} \right)}^{2}}+{{\left( \frac{a}{2} \right)}^{2}}+{{(0)}^{2}} \right]}^{1/2}}=\frac{a}{\sqrt{2}}\] |
| a being lattice constant. |
| \[\therefore \] \[a=\sqrt{2}\,r=\sqrt{2}\times 2.54=3.59\,\,{\AA}\] |
| Note: Interatomic spacing is just the nearest neighbours distance. |
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