NEET Physics Semiconducting Devices NEET PYQ-Semiconducting Devices

  • question_answer
    The truth table given below is for which gate?                                          [AIPMT 1998]
    Input Output
    A B C
    0 0 1
    0 1 1
    1 0 1
    1 1 0

    A)  XOR   

    B)                   OR

    C)  AND

    D)                   NAND

    Correct Answer: D

    Solution :

    The given truth table gives
                            \[0*0=1\]
                            \[0*1=1\]
                            \[1*0=1\]
                            \[1*1=0\]
                The above data represents the expression \[Y=\overline{A\,\,.\,\,B}\]
                This expression is the Boolean expression of NAND gate.
                Note:    NAND gate used as OR function
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                Thus     \[\overline{A\cdot B}=\overline{A}+\overline{B}\]
    This is according to De Morgan’s theorem which states that complements of produces equals the sum or vice-versa.


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