A) 0.1 V
B) 1.0 V
C) 1 mV
D) 10 Mv
Correct Answer: D
Solution :
| Current amplification factor \[\beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}\] |
| Collector resistance \[\Delta {{I}_{C}}=\frac{2\,V}{2\times {{10}^{3}}\Omega }=1\times {{10}^{-3}}A\] |
| Base current \[\Delta {{I}_{B}}=\frac{\,{{V}_{B}}}{{{R}_{B}}}=\frac{{{V}_{B}}}{1\times {{10}^{3}}}={{V}_{B}}\times {{10}^{-3}}\] |
| Given, \[\beta =100\] |
| Now, \[100=\frac{{{10}^{-3}}}{{{V}_{B}}\times {{10}^{-3}}}\] |
| \[{{V}_{B}}=\frac{1}{100}V=10\,mV\] |
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