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NEET Physics Semiconducting Devices NEET PYQ-Semiconducting Devices

  • question_answer
    In a CE transistor amplifier, the audio signal voltage across the collector resistance of \[2\,k\Omega \] is 2V. If the base resistance is \[1\,k\Omega \] and the current amplification of the transistor is 100, the input signal voltage is                            [AIPMT (S) 2012]

    A)  0.1 V      

    B)  1.0 V

    C)       1 mV    

    D)   10 Mv

    Correct Answer: D

    Solution :

    Current amplification factor \[\beta =\frac{\Delta {{I}_{C}}}{\Delta {{I}_{B}}}\]
    Collector resistance \[\Delta {{I}_{C}}=\frac{2\,V}{2\times {{10}^{3}}\Omega }=1\times {{10}^{-3}}A\]
    Base current \[\Delta {{I}_{B}}=\frac{\,{{V}_{B}}}{{{R}_{B}}}=\frac{{{V}_{B}}}{1\times {{10}^{3}}}={{V}_{B}}\times {{10}^{-3}}\]
    Given,   \[\beta =100\]
    Now,     \[100=\frac{{{10}^{-3}}}{{{V}_{B}}\times {{10}^{-3}}}\]
    \[{{V}_{B}}=\frac{1}{100}V=10\,mV\]


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