NEET Physics Semiconducting Devices NEET PYQ-Semiconducting Devices

  • question_answer
    A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of \[800\,\,\Omega \] is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is \[192\,\Omega ,\] the voltage gain and the power gain of the amplifier will respectively be :                                                                                                                      [NEET - 2016]

    A)  4, 3.84            

    B)       3.69, 3.84

    C)  4, 4                 

    D)       4, 3.69

    Correct Answer: A

    Solution :

    [a] Given \[\alpha =0.96\]
    So,       \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.96}{0.04}\Rightarrow \]
    Voltage gain for common emitter configuration
    \[{{A}_{v}}=\beta .\frac{{{R}_{L}}}{{{R}_{i}}}=24\times \frac{800}{192}=100\]
    Power gain for common emitter configuration
    \[{{P}_{v}}=\beta {{A}_{v}}=24\times 100=2400\]
    Voltage gain for common base configuration
    \[{{A}_{v}}=\alpha .\frac{{{R}_{L}}}{{{R}_{P}}}=0.96\times \frac{800}{192}=4\]
    Power gain for common base configuration
    \[{{P}_{v}}={{A}_{v}}\alpha =4\times 0.96=3.84\]
    *In the question it is asked about common emitter configuration but we got above answer for common base configuration.


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