NEET Physics Simple Harmonic Motion NEET PYQ-Simple Harmonic Motion

  • question_answer
    Two simple harmonic motions of angular frequency 100 and \[1000\text{ }rad~\,\,{{s}^{-1}}\] have the same displacement amplitude. The ratio of their maximum acceleration is                                                         [AIPMPT (S) 2008]

    A)  \[1\,\,:10\]

    B)                   \[1\,\,:{{10}^{2}}\]

    C)  \[1\,\,:{{10}^{3}}\]    

    D)       \[1\,\,:{{10}^{4}}\]

    Correct Answer: B

    Solution :

    Acceleration of simple harmonic motion is
    \[{{a}_{\max }}=-{{\omega }^{2}}A\]
    or         \[\frac{{{({{a}_{\max }})}_{1}}}{{{({{a}_{\max }})}_{2}}}=\frac{\omega _{1}^{2}}{\omega _{2}^{2}}\]  (as A remains same)
    or         \[\frac{{{({{a}_{\max }})}_{1}}}{{{({{a}_{\max }})}_{2}}}=\frac{{{(100)}^{2}}}{{{(1000)}^{2}}}={{\left( \frac{1}{10} \right)}^{2}}=1:{{10}^{2}}\]


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